Question
$$-4(2x+1)^2 = 0$$
Answer
$$ x = -\dfrac{ 1 }{ 2 } $$
Explanation
$$ \begin{aligned} -4(2x+1)^2 &= 0&& \text{simplify left side} \\[1 em]-4(4x^2+4x+1) &= 0&& \\[1 em]-(16x^2+16x+4) &= 0&& \\[1 em]-16x^2-16x-4 &= 0&& \\[1 em] \end{aligned} $$
$ -16x^{2}-16x-4 = 0 $ is a quadratic equation.
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