Question
$$-3(x+1)^2 = 27$$
Answer
$$ \begin{matrix}x_1 = -1+3i & x_2 = -1-3i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} -3(x+1)^2 &= 27&& \text{simplify left side} \\[1 em]-3(x^2+2x+1) &= 27&& \\[1 em]-(3x^2+6x+3) &= 27&& \\[1 em]-3x^2-6x-3 &= 27&& \text{move all terms to the left hand side } \\[1 em]-3x^2-6x-3-27 &= 0&& \text{simplify left side} \\[1 em]-3x^2-6x-30 &= 0&& \\[1 em] \end{aligned} $$
$ -3x^{2}-6x-30 = 0 $ is a quadratic equation.
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