Question
$$-2(x+4)(3x-1) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 1 }{ 3 } & x_2 = -4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} -2(x+4)(3x-1) &= 0&& \text{simplify left side} \\[1 em]-(2x+8)(3x-1) &= 0&& \\[1 em]-(6x^2-2x+24x-8) &= 0&& \\[1 em]-(6x^2+22x-8) &= 0&& \\[1 em]-6x^2-22x+8 &= 0&& \\[1 em] \end{aligned} $$
$ -6x^{2}-22x+8 = 0 $ is a quadratic equation.
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