Question
$$-2(3x+4)(3x-4) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 4 }{ 3 } & x_2 = -\dfrac{ 4 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} -2(3x+4)(3x-4) &= 0&& \text{simplify left side} \\[1 em]-(6x+8)(3x-4) &= 0&& \\[1 em]-(18x^2-24x+24x-32) &= 0&& \\[1 em]-(18x^2-32) &= 0&& \\[1 em]-18x^2+32 &= 0&& \\[1 em] \end{aligned} $$
$ -18x^{2}+32 = 0 $ is a quadratic equation.
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