Question
$$-16x^2+16x+192 = 2$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 1 }{ 2 }-\dfrac{\sqrt{ 194 }}{ 4 } & x_2 = \dfrac{ 1 }{ 2 }+\dfrac{\sqrt{ 194 }}{ 4 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} -16x^2+16x+192 &= 2&& \text{move all terms to the left hand side } \\[1 em]-16x^2+16x+192-2 &= 0&& \text{simplify left side} \\[1 em]-16x^2+16x+190 &= 0&& \\[1 em] \end{aligned} $$
$ -16x^{2}+16x+190 = 0 $ is a quadratic equation.
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