Question
$$-10\cdot(1-9x)+6(x-10) = 0$$
Answer
$$ x = \dfrac{35}{48} $$
Explanation
$$ \begin{aligned} -10\cdot(1-9x)+6(x-10) &= 0&& \text{simplify left side} \\[1 em]-(10-90x)+6x-60 &= 0&& \\[1 em]-10+90x+6x-60 &= 0&& \\[1 em]96x-70 &= 0&& \text{ move the constants to the right } \\[1 em]96x &= 70&& \text{ divide both sides by $ 96 $ } \\[1 em]x &= \frac{70}{96}&& \\[1 em]x &= \frac{35}{48}&& \\[1 em] \end{aligned} $$
This page was created using
Equations Solver