Question
$$5+6-4+4\cdot\frac{3}{1}\cdot61-5 = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} 5+6-4+4\cdot\frac{3}{1}\cdot61-5 &= 0&& \text{multiply ALL terms by } \color{blue}{ 1 }. \\[1 em]1\cdot5+1\cdot6-1\cdot4+14\cdot\frac{3}{1}\cdot61-1\cdot5 &= 1\cdot0&& \text{cancel out the denominators} \\[1 em]5+6-4+732-5 &= 0&& \text{simplify left side} \\[1 em]5+6-4+732-5 &= 0&& \\[1 em]734 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 734 = 0 } $ is FALSE, we conclude that the equation has no solution.
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