$$ \begin{aligned} 4-3(x-1) &= 5x&& \text{simplify left side} \\[1 em]4-(3x-3) &= 5x&& \\[1 em]4-3x+3 &= 5x&& \\[1 em]-3x+7 &= 5x&& \text{move the $ \color{blue}{ 5x } $ to the left side and $ \color{blue}{ 7 }$ to the right} \\[1 em]-3x-5x &= -7&& \text{simplify left side} \\[1 em]-8x &= -7&& \text{ divide both sides by $ -8 $ } \\[1 em]x &= \frac{-7}{-8}&& \\[1 em]x &= \frac{7}{8}&& \\[1 em] \end{aligned} $$

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