Question
$$17-3x\cdot(2+3) = 0$$
Answer
$$ x = \dfrac{17}{15} $$
Explanation
$$ \begin{aligned} 17-3x\cdot(2+3) &= 0&& \text{simplify left side} \\[1 em]17-3x\cdot5 &= 0&& \\[1 em]17-15x &= 0&& \\[1 em]-15x+17 &= 0&& \text{ move the constants to the right } \\[1 em]-15x &= -17&& \text{ divide both sides by $ -15 $ } \\[1 em]x &= \frac{-17}{-15}&& \\[1 em]x &= \frac{17}{15}&& \\[1 em] \end{aligned} $$
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