Question
$$10-\frac{15}{3}+1\cdot(3-8) = 0$$
Answer
The equation has an infinite number of solutions.
Explanation
$$ \begin{aligned} 10-\frac{15}{3}+1\cdot(3-8) &= 0&& \text{multiply ALL terms by } \color{blue}{ 3 }. \\[1 em]3\cdot10-3\cdot\frac{15}{3}+3\cdot1\cdot(3-8) &= 3\cdot0&& \text{cancel out the denominators} \\[1 em]30-15+(-15) &= 0&& \text{simplify left side} \\[1 em]30-15+(-15) &= 0&& \\[1 em]0 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{blue}{ 0 = 0 } $ is TRUE for any value of $ x $, we conclude that the equation has infinitely many solutions.
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