Question
$$\frac{6x+8}{3x}\cdot9 = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = -\dfrac{ 4 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{6x+8}{3x}\cdot9 &= 0&& \text{multiply ALL terms by } \color{blue}{ 3x }. \\[1 em]3x \cdot \frac{6x+8}{3x}\cdot9 &= 3x\cdot0&& \text{cancel out the denominators} \\[1 em]54x^3+72x^2 &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 54x^{3}+72x^{2} = 0 } $, first we need to factor our $ x^2 $.
$$ 54x^{3}+72x^{2} = x^2 \left( 54x+72 \right) $$$ x = 0 $ is a root of multiplicity $ 2 $.
The second root can be found by solving equation $ 54x+72 = 0$.
This page was created using
Equations Solver