Question
$$(x-2+x+3)(x+2-(x+3)) = 0$$
Answer
$$ x = -\dfrac{1}{2} $$
Explanation
$$ \begin{aligned} (x-2+x+3)(x+2-(x+3)) &= 0&& \text{simplify left side} \\[1 em](2x+1)(x+2-(x+3)) &= 0&& \\[1 em](2x+1)(x+2-x-3) &= 0&& \\[1 em](2x+1)\cdot(-1) &= 0&& \\[1 em]-2x-1 &= 0&& \text{ move the constants to the right } \\[1 em]-2x &= 1&& \text{ divide both sides by $ -2 $ } \\[1 em]x &= -\frac{1}{2}&& \\[1 em] \end{aligned} $$
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