Question
$$(x+8)(3x-1) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 1 }{ 3 } & x_2 = -8 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+8)(3x-1) &= 0&& \text{simplify left side} \\[1 em]3x^2-x+24x-8 &= 0&& \\[1 em]3x^2+23x-8 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}+23x-8 = 0 $ is a quadratic equation.
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