Question
$$(x+5)\cdot2x = 58$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 5 }{ 2 }-\dfrac{\sqrt{ 141 }}{ 2 } & x_2 = -\dfrac{ 5 }{ 2 }+\dfrac{\sqrt{ 141 }}{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+5)\cdot2x &= 58&& \text{simplify left side} \\[1 em](2x+10)x &= 58&& \\[1 em]2x^2+10x &= 58&& \text{move all terms to the left hand side } \\[1 em]2x^2+10x-58 &= 0&& \\[1 em] \end{aligned} $$
$ 2x^{2}+10x-58 = 0 $ is a quadratic equation.
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