Question
$$(x+4)\frac{x+2}{x+2}(x+9) = 0$$
Answer
$$ \begin{matrix}x_1 = -4 & x_2 = -9 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+4)\frac{x+2}{x+2}(x+9) &= 0&& \text{simplify left side} \\[1 em](x+4)\cdot1(x+9) &= 0&& \\[1 em](x+4)(x+9) &= 0&& \\[1 em]x^2+9x+4x+36 &= 0&& \\[1 em]x^2+13x+36 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+13x+36 = 0 $ is a quadratic equation.
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