Question
$$(x+3)^2-3(x+3)+8 = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 3 }{ 2 }+\dfrac{\sqrt{ 23 }}{ 2 }i & x_2 = -\dfrac{ 3 }{ 2 }-\dfrac{\sqrt{ 23 }}{ 2 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+3)^2-3(x+3)+8 &= 0&& \text{simplify left side} \\[1 em]x^2+6x+9-3(x+3)+8 &= 0&& \\[1 em]x^2+6x+9-(3x+9)+8 &= 0&& \\[1 em]x^2+6x+9-3x-9+8 &= 0&& \\[1 em]x^2+6x+9-3x-9+8 &= 0&& \\[1 em]x^2+3x+8 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+3x+8 = 0 $ is a quadratic equation.
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