Question
$$(x+3)^2-1 = 35$$
Answer
$$ \begin{matrix}x_1 = 3 & x_2 = -9 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+3)^2-1 &= 35&& \text{simplify left side} \\[1 em]x^2+6x+9-1 &= 35&& \\[1 em]x^2+6x+8 &= 35&& \text{move all terms to the left hand side } \\[1 em]x^2+6x+8-35 &= 0&& \text{simplify left side} \\[1 em]x^2+6x-27 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+6x-27 = 0 $ is a quadratic equation.
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