Question
$$(x\cdot3+5x\cdot2-2x+1)(x-7) = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 1 }{ 11 } & x_2 = 7 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x\cdot3+5x\cdot2-2x+1)(x-7) &= 0&& \text{simplify left side} \\[1 em](3x+10x-2x+1)(x-7) &= 0&& \\[1 em](11x+1)(x-7) &= 0&& \\[1 em]11x^2-77x+x-7 &= 0&& \\[1 em]11x^2-76x-7 &= 0&& \\[1 em] \end{aligned} $$
$ 11x^{2}-76x-7 = 0 $ is a quadratic equation.
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