$$ \begin{aligned} x\cdot3-5x\cdot2-22x-16+x+2 &= 0&& \text{simplify left side} \\[1 em]3x-10x-22x-16+x+2 &= 0&& \\[1 em]-29x-16+x+2 &= 0&& \\[1 em]-28x-14 &= 0&& \text{ move the constants to the right } \\[1 em]-28x &= 14&& \text{ divide both sides by $ -28 $ } \\[1 em]x &= -\frac{14}{28}&& \\[1 em]x &= -\frac{1}{2}&& \\[1 em] \end{aligned} $$

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