Question
$$(x\cdot2-4x+3)(x\cdot2-4x+4) = 20$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 1 }{ 2 } & x_2 = 4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x\cdot2-4x+3)(x\cdot2-4x+4) &= 20&& \text{simplify left side} \\[1 em](-2x+3)(-2x+4) &= 20&& \\[1 em]4x^2-8x-6x+12 &= 20&& \\[1 em]4x^2-14x+12 &= 20&& \text{move all terms to the left hand side } \\[1 em]4x^2-14x+12-20 &= 0&& \text{simplify left side} \\[1 em]4x^2-14x-8 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}-14x-8 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Equations Solver