Question
$$(x-8)^2 = 6(x+5)$$
Answer
$$ \begin{matrix}x_1 = 11-\sqrt{ 87 } & x_2 = 11+\sqrt{ 87 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-8)^2 &= 6(x+5)&& \text{simplify left and right hand side} \\[1 em]x^2-16x+64 &= 6x+30&& \text{move all terms to the left hand side } \\[1 em]x^2-16x+64-6x-30 &= 0&& \text{simplify left side} \\[1 em]x^2-22x+34 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-22x+34 = 0 $ is a quadratic equation.
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