Question
$$(x-8)(x+0) = 6$$
Answer
$$ \begin{matrix}x_1 = 4-\sqrt{ 22 } & x_2 = 4+\sqrt{ 22 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-8)(x+0) &= 6&& \text{simplify left side} \\[1 em]x^2+0x-8x+0 &= 6&& \\[1 em]x^2+0x-8x+0 &= 6&& \\[1 em]x^2-8x &= 6&& \text{move all terms to the left hand side } \\[1 em]x^2-8x-6 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-8x-6 = 0 $ is a quadratic equation.
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