$$ \begin{aligned} (x-7)^2 &= (x+3)^2&& \text{simplify left and right hand side} \\[1 em]x^2-14x+49 &= x^2+6x+9&& \text{move all terms to the left hand side } \\[1 em]x^2-14x+49-x^2-6x-9 &= 0&& \text{simplify left side} \\[1 em]x^2-14x+49-x^2-6x-9 &= 0&& \\[1 em]-20x+40 &= 0&& \text{ move the constants to the right } \\[1 em]-20x &= -40&& \text{ divide both sides by $ -20 $ } \\[1 em]x &= \frac{-40}{-20}&& \\[1 em]x &= 2&& \\[1 em] \end{aligned} $$

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