Question
$$(x-5)(x+6) = 8$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 1 }{ 2 }-\dfrac{ 3 \sqrt{ 17}}{ 2 } & x_2 = -\dfrac{ 1 }{ 2 }+\dfrac{ 3 \sqrt{ 17}}{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-5)(x+6) &= 8&& \text{simplify left side} \\[1 em]x^2+6x-5x-30 &= 8&& \\[1 em]x^2+x-30 &= 8&& \text{move all terms to the left hand side } \\[1 em]x^2+x-30-8 &= 0&& \text{simplify left side} \\[1 em]x^2+x-38 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+x-38 = 0 $ is a quadratic equation.
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