Question
$$(x-4)\cdot5x = 44$$
Answer
$$ \begin{matrix}x_1 = 2-\dfrac{ 8 \sqrt{ 5}}{ 5 } & x_2 = 2+\dfrac{ 8 \sqrt{ 5}}{ 5 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-4)\cdot5x &= 44&& \text{simplify left side} \\[1 em](5x-20)x &= 44&& \\[1 em]5x^2-20x &= 44&& \text{move all terms to the left hand side } \\[1 em]5x^2-20x-44 &= 0&& \\[1 em] \end{aligned} $$
$ 5x^{2}-20x-44 = 0 $ is a quadratic equation.
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