$$ \begin{aligned} (x-\frac{3}{10})(x+\frac{7}{10}) &= 0&& \text{simplify left side} \\[1 em]\frac{10x-3}{10}\frac{10x+7}{10} &= 0&& \\[1 em]\frac{100x^2+40x-21}{100} &= 0&& \text{multiply ALL terms by } \color{blue}{ 100 }. \\[1 em]100 \cdot \frac{100x^2+40x-21}{100} &= 100\cdot0&& \text{cancel out the denominators} \\[1 em]100x^2+40x-21 &= 0&& \\[1 em] \end{aligned} $$
$ 100x^{2}+40x-21 = 0 $ is a quadratic equation.
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