Question
$$(x-3)^2 = (2x+7)^2$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 4 }{ 3 } & x_2 = -10 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-3)^2 &= (2x+7)^2&& \text{simplify left and right hand side} \\[1 em]x^2-6x+9 &= 4x^2+28x+49&& \text{move all terms to the left hand side } \\[1 em]x^2-6x+9-4x^2-28x-49 &= 0&& \text{simplify left side} \\[1 em]-3x^2-34x-40 &= 0&& \\[1 em] \end{aligned} $$
$ -3x^{2}-34x-40 = 0 $ is a quadratic equation.
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