Question
$$(x-2)(3x-4) = 0$$
Answer
$$ \begin{matrix}x_1 = 2 & x_2 = \dfrac{ 4 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-2)(3x-4) &= 0&& \text{simplify left side} \\[1 em]3x^2-4x-6x+8 &= 0&& \\[1 em]3x^2-10x+8 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}-10x+8 = 0 $ is a quadratic equation.
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