Question
$$\frac{x-2}{x^2+4x+3} = 0$$
Answer
$$ x = 2 $$
Explanation
$$ \begin{aligned} \frac{x-2}{x^2+4x+3} &= 0&& \text{multiply ALL terms by } \color{blue}{ x^2+4x+3 }. \\[1 em](x^2+4x+3)\frac{x-2}{x^2+4x+3} &= (x^2+4x+3)\cdot0&& \text{cancel out the denominators} \\[1 em]x-2 &= 0&& \text{ move the constants to the right } \\[1 em]x &= 2&& \\[1 em]x &= 2&& \\[1 em] \end{aligned} $$
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