Question
$$(x-2)(x-8) = 0$$
Answer
$$ \begin{matrix}x_1 = 2 & x_2 = 8 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-2)(x-8) &= 0&& \text{simplify left side} \\[1 em]x^2-8x-2x+16 &= 0&& \\[1 em]x^2-10x+16 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-10x+16 = 0 $ is a quadratic equation.
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