Question
$$x^2+4x+4-(x^2-6x+9) = 0$$
Answer
$$ x = \dfrac{1}{2} $$
Explanation
$$ \begin{aligned} x^2+4x+4-(x^2-6x+9) &= 0&& \text{simplify left side} \\[1 em]x^2+4x+4-x^2+6x-9 &= 0&& \\[1 em]x^2+4x+4-x^2+6x-9 &= 0&& \\[1 em]10x-5 &= 0&& \text{ move the constants to the right } \\[1 em]10x &= 5&& \text{ divide both sides by $ 10 $ } \\[1 em]x &= \frac{5}{10}&& \\[1 em]x &= \frac{1}{2}&& \\[1 em] \end{aligned} $$
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