Question
$$(x^2+4)(x^3+2x-4) = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} (x^2+4)(x^3+2x-4) &= 0&& \text{simplify left side} \\[1 em]x^5+2x^3-4x^2+4x^3+8x-16 &= 0&& \\[1 em]x^5+6x^3-4x^2+8x-16 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using Newton method.
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