Question
$$\frac{x^2+2}{x^2+1}\cdot1 = 0$$
Answer
$$ \begin{matrix}x_1 = \sqrt{ 2 } i & x_2 = -\sqrt{ 2 } i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{x^2+2}{x^2+1}\cdot1 &= 0&& \text{multiply ALL terms by } \color{blue}{ x^2+1 }. \\[1 em](x^2+1)\frac{x^2+2}{x^2+1}\cdot1 &= (x^2+1)\cdot0&& \text{cancel out the denominators} \\[1 em]x^2+2 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+2 = 0 $ is a quadratic equation.
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