Question
$$(x^2+1)(x^4+1)(x^8+1) = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} (x^2+1)(x^4+1)(x^8+1) &= 0&& \text{simplify left side} \\[1 em](x^6+x^2+x^4+1)(x^8+1) &= 0&& \\[1 em]x^{14}+x^{12}+x^{10}+x^8+x^6+x^4+x^2+1 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using Newton method.
This page was created using
Equations Solver