Question
$$\frac{x^2+x-12}{x^2-9} = 0$$
Answer
$$ \begin{matrix}x_1 = 3 & x_2 = -4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{x^2+x-12}{x^2-9} &= 0&& \text{multiply ALL terms by } \color{blue}{ x^2-9 }. \\[1 em](x^2-9)\frac{x^2+x-12}{x^2-9} &= (x^2-9)\cdot0&& \text{cancel out the denominators} \\[1 em]x^2+x-12 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+x-12 = 0 $ is a quadratic equation.
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