$$ \begin{aligned} \frac{t^2+1}{t}-2 &= 0&& \text{multiply ALL terms by } \color{blue}{ t }. \\[1 em]t\frac{t^2+1}{t}-t\cdot2 &= t\cdot0&& \text{cancel out the denominators} \\[1 em]t^2+1-2t &= 0&& \text{simplify left side} \\[1 em]t^2-2t+1 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-2x+1 = 0 $ is a quadratic equation.
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