Question
$$(r-3)(r-3) = 0$$
Answer
$$ r = 3 $$
Explanation
$$ \begin{aligned} (r-3)(r-3) &= 0&& \text{simplify left side} \\[1 em]r^2-3r-3r+9 &= 0&& \\[1 em]r^2-6r+9 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-6x+9 = 0 $ is a quadratic equation.
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