Question
$$(i-5)(i-3) = 0$$
Answer
$$ \begin{matrix}i_1 = 3 & i_2 = 5 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (i-5)(i-3) &= 0&& \text{simplify left side} \\[1 em]i^2-3i-5i+15 &= 0&& \\[1 em]i^2-8i+15 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-8x+15 = 0 $ is a quadratic equation.
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