Question
$$9x-6-(8x^2+2x-1) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 7 }{ 16 }+\dfrac{\sqrt{ 111 }}{ 16 }i & x_2 = \dfrac{ 7 }{ 16 }-\dfrac{\sqrt{ 111 }}{ 16 }i \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 9x-6-(8x^2+2x-1) &= 0&& \text{simplify left side} \\[1 em]9x-6-8x^2-2x+1 &= 0&& \\[1 em]-8x^2+7x-5 &= 0&& \\[1 em] \end{aligned} $$
$ -8x^{2}+7x-5 = 0 $ is a quadratic equation.
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