Question
$$(9c-2)\cdot(4-2c) = 0$$
Answer
$$ \begin{matrix}c_1 = 2 & c_2 = \dfrac{ 2 }{ 9 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (9c-2)\cdot(4-2c) &= 0&& \text{simplify left side} \\[1 em]36c-18c^2-8+4c &= 0&& \\[1 em]-18c^2+40c-8 &= 0&& \\[1 em] \end{aligned} $$
$ -18x^{2}+40x-8 = 0 $ is a quadratic equation.
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