Question
$$\frac{8x-3}{x+4} = 0$$
Answer
$$ x = \dfrac{3}{8} $$
Explanation
$$ \begin{aligned} \frac{8x-3}{x+4} &= 0&& \text{multiply ALL terms by } \color{blue}{ x+4 }. \\[1 em](x+4)\frac{8x-3}{x+4} &= (x+4)\cdot0&& \text{cancel out the denominators} \\[1 em]8x-3 &= 0&& \text{ move the constants to the right } \\[1 em]8x &= 3&& \text{ divide both sides by $ 8 $ } \\[1 em]x &= \frac{3}{8}&& \\[1 em] \end{aligned} $$
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