Question
$$(8+\frac{24}{\frac{42}{3}\cdot2-20})^2 = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} (8+\frac{24}{\frac{42}{3}\cdot2-20})^2 &= 0&& \text{multiply ALL terms by } \color{blue}{ 24 }. \\[1 em]24(8+\frac{24}{\frac{42}{3}\cdot2-20})^2 &= 24\cdot0&& \text{cancel out the denominators} \\[1 em]2904 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 2904 = 0 } $ is FALSE, we conclude that the equation has no solution.
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