Question
$$(7y+2)\cdot2+112 = 0$$
Answer
$$ y = -\dfrac{58}{7} $$
Explanation
$$ \begin{aligned} (7y+2)\cdot2+112 &= 0&& \text{simplify left side} \\[1 em]14y+4+112 &= 0&& \\[1 em]14y+116 &= 0&& \text{ move the constants to the right } \\[1 em]14y &= -116&& \text{ divide both sides by $ 14 $ } \\[1 em]y &= -\frac{116}{14}&& \\[1 em]y &= -\frac{58}{7}&& \\[1 em] \end{aligned} $$
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