Question
$$(7t-2)(2t+2) = 0$$
Answer
$$ \begin{matrix}t_1 = -1 & t_2 = \dfrac{ 2 }{ 7 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (7t-2)(2t+2) &= 0&& \text{simplify left side} \\[1 em]14t^2+14t-4t-4 &= 0&& \\[1 em]14t^2+10t-4 &= 0&& \\[1 em] \end{aligned} $$
$ 14x^{2}+10x-4 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
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