Question
$$(7-5)^3x\cdot\frac{9}{4} = 0$$
Answer
$$ x = 0 $$
Explanation
$$ \begin{aligned} (7-5)^3x\cdot\frac{9}{4} &= 0&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]4(7-5)^3x\cdot\frac{9}{4} &= 4\cdot0&& \text{cancel out the denominators} \\[1 em]72x &= 0&& \text{ divide both sides by $ 72 $ } \\[1 em]x &= \frac{0}{72}&& \\[1 em]x &= 0&& \\[1 em] \end{aligned} $$
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