$$ \begin{aligned} 6x\cdot7+8x-2-(x\cdot3+2x\cdot2-x-3) &= 0&& \text{simplify left side} \\[1 em]42x+8x-2-(3x+4x-x-3) &= 0&& \\[1 em]50x-2-(6x-3) &= 0&& \\[1 em]50x-2-6x+3 &= 0&& \\[1 em]44x+1 &= 0&& \text{ move the constants to the right } \\[1 em]44x &= -1&& \text{ divide both sides by $ 44 $ } \\[1 em]x &= -\frac{1}{44}&& \\[1 em] \end{aligned} $$

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