Question
$$(6x^8-4x^5-1)(3x^2-4) = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} (6x^8-4x^5-1)(3x^2-4) &= 0&& \text{simplify left side} \\[1 em]18x^{10}-24x^8-12x^7+16x^5-3x^2+4 &= 0&& \\[1 em] \end{aligned} $$
This polynomial has no rational roots that can be found using Rational Root Test.
Roots were found using Newton method.
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