$$ \begin{aligned} \frac{6+4}{5}x\cdot3-1 &= 0&& \text{multiply ALL terms by } \color{blue}{ 5 }. \\[1 em]5 \cdot \frac{6+4}{5}x\cdot3-5\cdot1 &= 5\cdot0&& \text{cancel out the denominators} \\[1 em]30x-5 &= 0&& \text{ move the constants to the right } \\[1 em]30x &= 5&& \text{ divide both sides by $ 30 $ } \\[1 em]x &= \frac{5}{30}&& \\[1 em]x &= \frac{1}{6}&& \\[1 em] \end{aligned} $$

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