Question
$$(5y+2)^2-112 = 0$$
Answer
$$ \begin{matrix}y_1 = -\dfrac{ 2 }{ 5 }-\dfrac{ 4 \sqrt{ 7}}{ 5 } & y_2 = -\dfrac{ 2 }{ 5 }+\dfrac{ 4 \sqrt{ 7}}{ 5 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (5y+2)^2-112 &= 0&& \text{simplify left side} \\[1 em]25y^2+20y+4-112 &= 0&& \\[1 em]25y^2+20y-108 &= 0&& \\[1 em] \end{aligned} $$
$ 25x^{2}+20x-108 = 0 $ is a quadratic equation.
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