$$ \begin{aligned} \frac{5y-3}{4}+6 &= 3y&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]4 \cdot \frac{5y-3}{4}+4\cdot6 &= 4\cdot3y&& \text{cancel out the denominators} \\[1 em]5y-3+24 &= 12y&& \text{simplify left side} \\[1 em]5y+21 &= 12y&& \text{move the $ \color{blue}{ 12y } $ to the left side and $ \color{blue}{ 21 }$ to the right} \\[1 em]5y-12y &= -21&& \text{simplify left side} \\[1 em]-7y &= -21&& \text{ divide both sides by $ -7 $ } \\[1 em]y &= \frac{-21}{-7}&& \\[1 em]y &= 3&& \\[1 em] \end{aligned} $$

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